SUM Handling Overflow - NOVLSHRT
SUM Handling Overflow - NOVLSHRT Example
Scenario - Sum the marks at department level.
Input File - MATEPK.SORT.INPUT02
----+----1----+----2----+----3----+----4----+----5----+----6----+----7----+----8 00001 student1 dept1 560 00002 student2 dept3 510 00003 student3 dept2 520 00004 student4 dept1 540 00005 student5 dept2 500
JCL -
----+----1----+----2----+----3----+----4----+----5----+
//MATEPKD JOB (123),'MTH',NOTIFY=&SYSUID
//*
//STEP01 EXEC PGM=SORT
//SORTIN DD DSN=MATEPK.SORT.INPUT02,DISP=SHR
//SORTOUT DD DSN=MATEPK.MERGE.OUTPUT,
// DISP=(NEW,CATLG,DELETE),UNIT=SYSDA,
// SPACE=(CYL,(1,4),RLSE),
// DCB=(RECFM=FB,LRECL=80,BLKSIZE=0)
//SYSOUT DD SYSOUT=*
//SYSIN DD *
OPTION NOVLSHRT
SORT FIELDS=(30,10,CH,A)
SUM FIELDS=(45,03,ZD)
/*
Output -
DFSORT terminates the job because of the overflow
Explaining Example -
- The summing of the marks at department level was not happened because there is an overflow if 560 and 510 added.
- The total exceeds 999 which is the maximum value in 3 bytes. So the DFSROT terminates the job.